Questions: Запишите разложение определителя по 2 -й строке
1 -5 -3
a b c
-2 2 5
=□ a+□ b+□ c
Проверить
Transcript text: Запишите разложение определителя по 2 -й строке
\[
\left|\begin{array}{ccc}
1 & -5 & -3 \\
a & b & c \\
-2 & 2 & 5
\end{array}\right|=\square a+\square b+\square c
\]
Проверить
Solution
Solution Steps
Step 1: Calculate Determinants of 2x2 Matrices
To find the determinant of the original 3x3 matrix using cofactor expansion along the second row, we first need to calculate the determinants of the following 2x2 matrices:
For \( a \):
\[
\left|\begin{matrix}-5 & -3\\2 & 5\end{matrix}\right| = (-1)^0 \times (-5) \times \frac{19}{5} = -19.00
\]
For \( b \):
\[
\left|\begin{matrix}1 & -3\\-2 & 5\end{matrix}\right| = (-1)^1 \times (-2) \times \left(-\frac{1}{2}\right) = -1.00
\]
For \( c \):
\[
\left|\begin{matrix}1 & -5\\-2 & 2\end{matrix}\right| = (-1)^1 \times (-2) \times (-4) = -8.00
\]
Step 2: Formulate the Determinant Expansion
Using the determinants calculated above, we can express the determinant of the original matrix as follows:
\[
\left|\begin{array}{ccc}
1 & -5 & -3 \\
a & b & c \\
-2 & 2 & 5
\end{array}\right| = -19.00 \cdot a - (-1.00) \cdot b - 8.00 \cdot c
\]
This simplifies to:
\[
\left|\begin{array}{ccc}
1 & -5 & -3 \\
a & b & c \\
-2 & 2 & 5
\end{array}\right| = -19.00 a + 1.00 b - 8.00 c
\]
Final Answer
The determinant expansion is given by:
\[
\boxed{\left|\begin{array}{ccc}
1 & -5 & -3 \\
a & b & c \\
-2 & 2 & 5
\end{array}\right| = -19.00 a + 1.00 b - 8.00 c}
\]