Questions: Solve for r to two decimal places. 5=e^(3r) r ≈ (Do not round until the final answer. Then round to the nearest hundredth as needed.)

Solve for r to two decimal places.
5=e^(3r)
r ≈ 
(Do not round until the final answer. Then round to the nearest hundredth as needed.)
Transcript text: Solve for $r$ to two decimal places. \[ 5=e^{3 r} \] $r \approx$ $\square$ (Do not round until the final answer. Then round to the nearest hundredth as needed.)
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Solution

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Solution Steps

Step 1: Start with the general form of the equation

The general form of the equation is $k = e^{m r}$, where $k$ and $m$ are constants.

Step 2: Take the natural logarithm (ln) of both sides

Taking the natural logarithm of both sides gives us $\ln(k) = \ln(e^{m r})$.

Step 3: Use the property of logarithms

Using the property that $\ln(e^x) = x$, we simplify the right side to $m r$.

Step 4: Simplify the equation

After simplification, we have $\ln(k) = m r$.

Step 5: Solve for $r$

Solving for $r$ gives $r = \frac{\ln(k)}{m} = \frac{\ln(5)}{3} = 0.54$.

Final Answer: The value of $r$ rounded to 2 decimal places is 0.54.

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