Questions: Problem 2: (6% of Assignment Value) A skydiver descends d1=315 meters in t1=8.9 s before letting out his parachute. After the chute opens, he descends an additional d2=895 meters in t2=132 s. See the figure. - Part (a) Enter an expression for the skydiver's average speed, vavg, during the period before letting out the chute in terms of the given quantities. vavg, 1 = d1 / t1 Correct! - Part (b) Enter an expression for the skydiver's average speed, vavg,2, during the period after letting out the chute in terms of the given quantities. vavg 2 = d2 / t2 Correct: Part (c) Enter an expression for the skydiver's average speed during the entire fall, vavg, in terms of the given quantities. vavg =

Transcript text: Problem 2: ( $6 \%$ of Assignment Value) A skydiver decends $d_{1}=315$ meters in $t_{1}=8.9 \mathrm{~s}$ before letting out his parachute. After the chute opens, he decends an additional $d_{2}=895$ meters in $t_{2}=132 \mathrm{~s}$. See the figure. - Part (a) $\sqrt{ }$ Enter an expression for the skydiver's average speed, $v_{\text {avg, }}$, during the period before letting out the chute in terms of the given quantities. \[ v_{\text {avg }, 1}=\mathrm{d}_{1} / h_{1} \quad \boldsymbol{V} \text { Correct! } \] - Part (b) $\sqrt{ }$ Enter an expression for the skydiver's average speed, $v_{\text {avg,2 }}$, during the period after letting out the chute in terms of the given quantities. \[ v_{\text {avg } 2}=\mathrm{d}_{2} / t_{2} \] Correct: Part (c) Enter an expression for the skydiver's average speed during the entire fall, $v_{\text {avg }}$, in terms of the given quantities. \[ v_{\mathrm{avg}}= \]