Questions: Complete and balance each nuclear equation by supplying the missing particle. ₁₁²⁴Na → ₋₁⁰β + ₇₈¹⁷⁰Pt → ₂⁴α + ₅₄¹¹⁸Xe → ₅₃¹¹⁸I +

Solution Steps

In nuclear equations, we need to ensure that both the atomic number (Z) and the mass number (A) are conserved on both sides of the equation.

For $_{11}^{24}\text{Na} \longrightarrow {}_{-1}^{0}\beta + \square$

The atomic number must be conserved: 11 = -1 + Z Therefore, Z = 12

The mass number must be conserved: 24 = 0 + A Therefore, A = 24

The missing particle is $_{12}^{24}\text{Mg}$

For $_{78}^{170}\text{Pt} \longrightarrow {}_{2}^{4}\alpha + \square$

The atomic number must be conserved: 78 = 2 + Z Therefore, Z = 76

The mass number must be conserved: 170 = 4 + A Therefore, A = 166

The missing particle is $_{76}^{166}\text{Os}$

For $_{54}^{118}\text{Xe} \longrightarrow {}_{53}^{118}\text{I} + \square$

The atomic number must be conserved: 54 = 53 + Z Therefore, Z = 1

The mass number must be conserved: 118 = 118 + A Therefore, A = 0

The missing particle is $_{1}^{0}\text{e}^{+}$ (positron)

Final Answer