Questions: （A） 10x+40+9 （B）x+4+9 （C） 10(10x+4)+9 （A）3/-8 x+1/4+1/3+1/2=0 （B）3/- x+1/4+1/3+1/2=0 （C）3/-2 x+1/4+1/3+1/2=0 （A）(3x-9)/5+(2x-7)/4=1 （B） 987x-456=456+587x （C） 5/4(1/2 x-1/3 x-1/4 x)=0 （A）(y-3+1)/3+3 （B）(y-3+1)/3 （C） 3y-1 1．愤化用 (45x+52)+(21x+14)=24x+38 2．埥化佣 1/3(3x-6)+1/4(8-4x)=2X+4 3．却化第 (2x-4)/3-3(x-1)/2-1=-5x-19 4．脬方和式 (3x+2)+2[(x-1)-(2x+1)]=6 ，得 x=

（A） 10x+40+9 （B）x+4+9 （C） 10(10x+4)+9 （A）3/-8 x+1/4+1/3+1/2=0 （B）3/- x+1/4+1/3+1/2=0 （C）3/-2 x+1/4+1/3+1/2=0 （A）(3x-9)/5+(2x-7)/4=1 （B） 987x-456=456+587x （C） 5/4(1/2 x-1/3 x-1/4 x)=0 （A）(y-3+1)/3+3 （B）(y-3+1)/3 （C） 3y-1 1．愤化用 (45x+52)+(21x+14)=24x+38 2．埥化佣 1/3(3x-6)+1/4(8-4x)=2X+4 3．却化第 (2x-4)/3-3(x-1)/2-1=-5x-19 4．脬方和式 (3x+2)+2[(x-1)-(2x+1)]=6 ，得 x=
Transcript text: （A） $10 x+40+9$ （B）$x+4+9$ （C） $10(10 x+4)+9$ （A）$\frac{3}{-8} x+\frac{1}{4}+\frac{1}{3}+\frac{1}{2}=0$ （B）$\frac{3}{-} x+\frac{1}{4}+\frac{1}{3}+\frac{1}{2}=0$ （C）$\frac{3}{-2} x+\frac{1}{4}+\frac{1}{3}+\frac{1}{2}=0$ （A）$\frac{3 x-9}{5}+\frac{2 x-7}{4}=1$ （B） $987 x-456=456+587 x$ \[ \text { (C) } \frac{5}{4}\left(\frac{1}{2} x-\frac{1}{3} x-\frac{1}{4} x\right)=0 \] （A）$\frac{y-3+1}{3}+3$ （B）$\frac{y-3+1}{3}$ （C） $3 y-1$ 1．愤化用 $(45 x+52)+(21 x+14)=24 x+38$ 2．埥化佣 $\frac{1}{3}(3 x-6)+\frac{1}{4}(8-4 x)=2 X+4$ 3．却化第 $\frac{2 x-4}{3}-\frac{3(x-1)}{2}-1=-5 x-19$ 4．脬方和式 $(3 x+2)+2[(x-1)-(2 x+1)]=6$ ，得 $x=$
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Solution

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Solution Steps

Step 1: Simplifying the new three-digit number

The original two-digit number is represented as 10x + 4. When a 9 is appended to the right, it becomes a three-digit number. This new number is formed by multiplying the original number by 10 and adding 9. So, the expression is 10(10x + 4) + 9.

Step 2: Simplifying the expression

Distribute the 10: 100x + 40 + 9

Combine like terms: 100x + 49

Step 3: Determining the rotational symmetry

The question asks which figure has rotational symmetry with respect to the given triangle ABC. Only option (C) shows a rotation of triangle ABC.

Final Answer

  1. (C) 10(10x+4)+9
  2. (C)
  3. (A)
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