Questions: The slope of the line passing through points (x1, y1) and (x2, y2) is found using the formula (y2-y1)/(x2-x1). The line passing through the points (1,2) and (x, 5) is perpendicular to a line that has a slope of 1/3. What is the value of x ? A 10 B -2 C -4 D 0

The slope of the line passing through points (x1, y1) and (x2, y2) is found using the formula (y2-y1)/(x2-x1).

The line passing through the points (1,2) and (x, 5) is perpendicular to a line that has a slope of 1/3. What is the value of x ?

A 10
B -2
C -4
D 0
Transcript text: The slope of the line passing through points $\left(x_{1}, y_{1}\right)$ and $\left(x_{2}, y_{2}\right)$ is found using the formula $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$. The line passing through the points $(1,2)$ and $(x, 5)$ is perpendicular to a line that has a slope of $\frac{1}{3}$. What is the value of $x$ ? A 10 B -2 C -4 D 0
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Solution

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Solution Steps

To find the value of \( x \), we need to determine the slope of the line passing through the points \((1, 2)\) and \((x, 5)\). Since this line is perpendicular to a line with a slope of \(\frac{1}{3}\), its slope must be the negative reciprocal, which is \(-3\). We set up the equation for the slope \(\frac{5 - 2}{x - 1} = -3\) and solve for \( x \).

Step 1: Determine the Slope of the Perpendicular Line

The line passing through the points \((1, 2)\) and \((x, 5)\) is perpendicular to a line with a slope of \(\frac{1}{3}\). Therefore, the slope of our line must be the negative reciprocal of \(\frac{1}{3}\), which is \(-3\).

Step 2: Set Up the Slope Equation

The slope of the line through the points \((1, 2)\) and \((x, 5)\) is given by the formula: \[ \frac{5 - 2}{x - 1} = -3 \]

Step 3: Solve for \( x \)

Simplify and solve the equation: \[ \frac{3}{x - 1} = -3 \] Multiply both sides by \((x - 1)\) to eliminate the fraction: \[ 3 = -3(x - 1) \] Distribute the \(-3\): \[ 3 = -3x + 3 \] Subtract 3 from both sides: \[ 0 = -3x \] Divide by \(-3\): \[ x = 0 \]

Final Answer

The value of \( x \) is \(\boxed{0}\).

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