Questions: The equation of a circle is given in standard form. Complete parts a through c to follow the step by step process to sketch the graph of the circle. [ x^2+(y-4)^2=16 ] a) Determine the center and radius of the circle. The center of the circle is (Type an ordered pair.)

The equation of a circle is given in standard form. Complete parts a through c to follow the step by step process to sketch the graph of the circle.
[ x^2+(y-4)^2=16 ]
a) Determine the center and radius of the circle.

The center of the circle is 
(Type an ordered pair.)
Transcript text: The equation of a circle is given in standard form. Complete parts a through c to follow the step by step process to sketch the graph of the circle. \[ x^{2}+(y-4)^{2}=16 \] a) Determine the center and radius of the circle. The center of the circle is $\square$ (Type an ordered pair.)
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Solution

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Solution Steps

Step 1: Determine the center of the circle

The equation of the circle is given in the standard form: \[ x^{2}+(y-4)^{2}=16 \] The standard form of a circle's equation is: \[ (x-h)^{2} + (y-k)^{2} = r^{2} \] where \((h, k)\) is the center and \(r\) is the radius.

Comparing the given equation with the standard form, we find:

  • \(h = 0\)
  • \(k = 4\)

Thus, the center of the circle is \((0, 4)\).

Step 2: Determine the radius of the circle

From the equation: \[ x^{2}+(y-4)^{2}=16 \] we have \(r^{2} = 16\).

Taking the square root of both sides, we find: \[ r = \sqrt{16} = 4 \]

Final Answer

The center of the circle is \((0, 4)\) and the radius is \(4\).

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