Questions: CH3CO-O → + H2O → H+

CH3CO-O → + H2O → H+
Transcript text: $\mathrm{CH}_{3} \stackrel{\mathrm{O}}{\mathrm{C}}-\mathrm{O} \longrightarrow+\mathrm{H}_{2} \mathrm{O} \xrightarrow{\mathrm{H}^{+}}$
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Solution

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Solution Steps

Step 1: Chlorination of m-xylene

The reaction in part (d) involves the chlorination of m-xylene (1,3-dimethylbenzene) in the presence of a Lewis acid catalyst, FeCl₃ (formed from Fe and Cl₂). This is an electrophilic aromatic substitution reaction. Chlorine will substitute for a hydrogen on the aromatic ring.

Step 2: Identifying possible products

Due to the directing effects of the methyl groups, the chlorine atom can be added at three different positions on the ring. One product will have the chlorine _ortho_ to both methyl groups. The second will have the chlorine _ortho_ to one methyl group and _para_ to the other. The third product will have the chlorine _meta_ to both methyl groups.

Step 3: Drawing the products

The three possible products are:

  1. 2,4-dimethylchlorobenzene

  2. 2,6-dimethylchlorobenzene

  3. 3,5-dimethylchlorobenzene

Final Answer:

The three products of the chlorination of m-xylene are 2,4-dimethylchlorobenzene, 2,6-dimethylchlorobenzene, and 3,5-dimethylchlorobenzene.

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