Questions: Find y''.
y = sqrt(7x+10)
A. 7 / (2 sqrt(7x+10))
B. -49 / (4(7x+10)^(3/2))
C. -1 / (4(7x+10)^(3/2))
D. -49 sqrt(7x+10) / 4
Find y''.
y = sqrt(7x+10)
A. 7 / (2 sqrt(7x+10))
B. -49 / (4(7x+10)^(3/2))
C. -1 / (4(7x+10)^(3/2))
D. -49 sqrt(7x+10) / 4
Solution
Solution Steps
To find the second derivative \( y'' \) of the function \( y = \sqrt{7x + 10} \), we need to follow these steps:
Find the first derivative \( y' \) using the chain rule.
Find the second derivative \( y'' \) by differentiating \( y' \) again.
Step 1: Find the First Derivative
To find the first derivative of the function \( y = \sqrt{7x + 10} \), we apply the chain rule:
\[
y' = \frac{d}{dx}(\sqrt{7x + 10}) = \frac{7}{2\sqrt{7x + 10}}
\]
Step 2: Find the Second Derivative
Next, we differentiate \( y' \) to find the second derivative \( y'' \):
\[
y'' = \frac{d}{dx}\left(\frac{7}{2\sqrt{7x + 10}}\right) = -\frac{49}{4(7x + 10)^{3/2}}
\]
Final Answer
The second derivative is
\[
\boxed{y'' = -\frac{49}{4(7x + 10)^{3/2}}}
\]