Questions: Find y''. y = sqrt(7x+10) A. 7 / (2 sqrt(7x+10)) B. -49 / (4(7x+10)^(3/2)) C. -1 / (4(7x+10)^(3/2)) D. -49 sqrt(7x+10) / 4

Find y''. y = sqrt(7x+10) A. 7 / (2 sqrt(7x+10)) B. -49 / (4(7x+10)^(3/2)) C. -1 / (4(7x+10)^(3/2)) D. -49 sqrt(7x+10) / 4

Solution

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Solution Steps

To find the second derivative \( y'' \) of the function \( y = \sqrt{7x + 10} \), we need to follow these steps:

  1. Find the first derivative \( y' \) using the chain rule.
  2. Find the second derivative \( y'' \) by differentiating \( y' \) again.
Step 1: Find the First Derivative

To find the first derivative of the function \( y = \sqrt{7x + 10} \), we apply the chain rule: \[ y' = \frac{d}{dx}(\sqrt{7x + 10}) = \frac{7}{2\sqrt{7x + 10}} \]

Step 2: Find the Second Derivative

Next, we differentiate \( y' \) to find the second derivative \( y'' \): \[ y'' = \frac{d}{dx}\left(\frac{7}{2\sqrt{7x + 10}}\right) = -\frac{49}{4(7x + 10)^{3/2}} \]

Final Answer

The second derivative is \[ \boxed{y'' = -\frac{49}{4(7x + 10)^{3/2}}} \]

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