The given quadratic equation is:
\[ x^2 - 6x + 3 = 0 \]
Step 2: Move the constant term to the other side
To complete the square, we first move the constant term to the other side of the equation:
\[ x^2 - 6x = -3 \]
Step 3: Complete the square
To complete the square, we need to add and subtract the square of half the coefficient of \(x\) on the left side. The coefficient of \(x\) is -6, so half of it is -3, and its square is 9:
\[ x^2 - 6x + 9 = -3 + 9 \]
\[ (x - 3)^2 = 6 \]
Step 4: Solve for \(x\)
Now, take the square root of both sides:
\[ x - 3 = \pm \sqrt{6} \]
\[ x = 3 \pm \sqrt{6} \]
Final Answer
The solutions to the quadratic equation are:
\[ x = 3 + \sqrt{6} \]
\[ x = 3 - \sqrt{6} \]