Questions: Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arrow.
K2SO4(aq) + FeCl3(aq) → I
Transcript text: Question 4 of 34
Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arrow.
\[
\mathrm{K}_{2} \mathrm{SO}_{4}(\mathrm{aq})+\mathrm{FeCl}_{3}(\mathrm{aq}) \rightarrow \mathrm{I}
\]
Solution
Solution Steps
Step 1: Identify the Reactants and Possible Products
The reactants given are potassium sulfate (\(\mathrm{K}_2\mathrm{SO}_4\)) and iron(III) chloride (\(\mathrm{FeCl}_3\)). Both are aqueous solutions. When these two compounds react, they can potentially form iron(III) sulfate (\(\mathrm{Fe}_2(\mathrm{SO}_4)_3\)) and potassium chloride (\(\mathrm{KCl}\)).
Step 2: Determine the Reaction Type
This is a double displacement reaction, where the cations and anions of the reactants switch places to form new products.
Step 3: Write the Unbalanced Equation
The unbalanced equation for the reaction is:
\[
\mathrm{K}_2\mathrm{SO}_4(\mathrm{aq}) + \mathrm{FeCl}_3(\mathrm{aq}) \rightarrow \mathrm{Fe}_2(\mathrm{SO}_4)_3(\mathrm{aq}) + \mathrm{KCl}(\mathrm{aq})
\]
Step 4: Balance the Chemical Equation
To balance the equation, ensure that the number of each type of atom is the same on both sides of the equation.
Potassium (\(\mathrm{K}\)): 2 on the left, so we need 2 on the right.
Sulfate (\(\mathrm{SO}_4\)): 1 on the left, 3 on the right, so we need 3 \(\mathrm{K}_2\mathrm{SO}_4\) on the left.
Iron (\(\mathrm{Fe}\)): 2 on the right, so we need 2 \(\mathrm{FeCl}_3\) on the left.
Chlorine (\(\mathrm{Cl}\)): 6 on the left, so we need 6 \(\mathrm{KCl}\) on the right.
The balanced equation is:
\[
3\mathrm{K}_2\mathrm{SO}_4(\mathrm{aq}) + 2\mathrm{FeCl}_3(\mathrm{aq}) \rightarrow \mathrm{Fe}_2(\mathrm{SO}_4)_3(\mathrm{aq}) + 6\mathrm{KCl}(\mathrm{aq})
\]