Questions: Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arrow. K2SO4(aq) + FeCl3(aq) → I

Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arrow.
K2SO4(aq) + FeCl3(aq) → I
Transcript text: Question 4 of 34 Complete the balanced molecular chemical equation for the reaction below. If no reaction occurs, write NR after the reaction arrow. \[ \mathrm{K}_{2} \mathrm{SO}_{4}(\mathrm{aq})+\mathrm{FeCl}_{3}(\mathrm{aq}) \rightarrow \mathrm{I} \]
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Solution

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Solution Steps

Step 1: Identify the Reactants and Possible Products

The reactants given are potassium sulfate (\(\mathrm{K}_2\mathrm{SO}_4\)) and iron(III) chloride (\(\mathrm{FeCl}_3\)). Both are aqueous solutions. When these two compounds react, they can potentially form iron(III) sulfate (\(\mathrm{Fe}_2(\mathrm{SO}_4)_3\)) and potassium chloride (\(\mathrm{KCl}\)).

Step 2: Determine the Reaction Type

This is a double displacement reaction, where the cations and anions of the reactants switch places to form new products.

Step 3: Write the Unbalanced Equation

The unbalanced equation for the reaction is: \[ \mathrm{K}_2\mathrm{SO}_4(\mathrm{aq}) + \mathrm{FeCl}_3(\mathrm{aq}) \rightarrow \mathrm{Fe}_2(\mathrm{SO}_4)_3(\mathrm{aq}) + \mathrm{KCl}(\mathrm{aq}) \]

Step 4: Balance the Chemical Equation

To balance the equation, ensure that the number of each type of atom is the same on both sides of the equation.

  • Potassium (\(\mathrm{K}\)): 2 on the left, so we need 2 on the right.
  • Sulfate (\(\mathrm{SO}_4\)): 1 on the left, 3 on the right, so we need 3 \(\mathrm{K}_2\mathrm{SO}_4\) on the left.
  • Iron (\(\mathrm{Fe}\)): 2 on the right, so we need 2 \(\mathrm{FeCl}_3\) on the left.
  • Chlorine (\(\mathrm{Cl}\)): 6 on the left, so we need 6 \(\mathrm{KCl}\) on the right.

The balanced equation is: \[ 3\mathrm{K}_2\mathrm{SO}_4(\mathrm{aq}) + 2\mathrm{FeCl}_3(\mathrm{aq}) \rightarrow \mathrm{Fe}_2(\mathrm{SO}_4)_3(\mathrm{aq}) + 6\mathrm{KCl}(\mathrm{aq}) \]

Final Answer

\[ \boxed{3\mathrm{K}_2\mathrm{SO}_4(\mathrm{aq}) + 2\mathrm{FeCl}_3(\mathrm{aq}) \rightarrow \mathrm{Fe}_2(\mathrm{SO}_4)_3(\mathrm{aq}) + 6\mathrm{KCl}(\mathrm{aq})} \]

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