Questions: Question 9
0/1 pt
This question is not about solving the stated problem, but about understanding it.
A rocket is launched, and its height above sea level t seconds after launch is given by the equation h(t)=-4.9 t^2+1400 t+470.
a) From what height was the rocket launched?
To answer this question, we'd find: The t coordinate of the vertex ✓
b) What is the maximum height the rocket reaches?
To answer this question, we'd find: The h coordinate of the vertex ~
c) If the rocket will splash down in the ocean, when will it splash down?
To answer this question, we'd find: The h coordinate of the vertex ✓
Transcript text: Question 9
0/1 pt
This question is not about solving the stated problem, but about understanding it.
A rocket is launched, and its height above sea level $t$ seconds after launch is given by the equation $h(t)=-4.9 t^{2}+1400 t+470$.
a) From what height was the rocket launched?
To answer this question, we'd find: The t coordinate of the vertex $\checkmark$
b) What is the maximum height the rocket reaches?
To answer this question, we'd find: The $h$ coordinate of the vertex $\sim$
c) If the rocket will splash down in the ocean, when will it splash down?
To answer this question, we'd find: The $h$ coordinate of the vertex $\checkmark$
Solution
Solution Steps
Solution Approach
a) To find the height from which the rocket was launched, evaluate the height function \( h(t) \) at \( t = 0 \).
b) To find the maximum height the rocket reaches, determine the vertex of the parabola represented by the height function. The vertex form of a quadratic function gives the maximum height at the vertex.
c) To find when the rocket will splash down, solve for \( t \) when \( h(t) = 0 \).
Step 1: Height at Launch
To find the height from which the rocket was launched, we evaluate the height function \( h(t) \) at \( t = 0 \):
\[
h(0) = -4.9(0)^2 + 1400(0) + 470 = 470
\]
Thus, the height at launch is \( 470 \) meters.
Step 2: Maximum Height
To find the maximum height the rocket reaches, we calculate the vertex of the parabola. The time at which the maximum height occurs is given by:
\[
t = -\frac{b}{2a} = -\frac{1400}{2 \cdot -4.9} \approx 142.8571
\]
Substituting this value back into the height function:
\[
h\left(142.8571\right) = -4.9(142.8571)^2 + 1400(142.8571) + 470 \approx 100470
\]
Thus, the maximum height is \( 100470 \) meters.
Step 3: Time of Splash Down
To find when the rocket will splash down, we solve for \( t \) when \( h(t) = 0 \):
\[
h(t) = -4.9t^2 + 1400t + 470 = 0
\]
The solutions to this equation are approximately:
\[
t \approx -0.3353 \quad \text{and} \quad t \approx 286.0496
\]
Since time cannot be negative, the time when the rocket splashes down is approximately \( 286.0496 \) seconds.
Final Answer
The answers to the questions are:
a) Height at launch: \( \boxed{470} \)
b) Maximum height: \( \boxed{100470} \)
c) Time of splash down: \( \boxed{286.0496} \) seconds.