Questions: Identify the vertex for the equation y=(x+5)^2-4 A. (5,-4) B. (-5,-4) C. (5,4) D. (-5,4)

Solution Steps

To find the vertex of a quadratic equation in the form \( y = (x-h)^2 + k \), the vertex is given by the point \((h, k)\). In the given equation \( y = (x+5)^2 - 4 \), we can identify \( h \) and \( k \) by comparing it to the standard form. Here, \( h = -5 \) and \( k = -4 \).

The given equation is \( y = (x+5)^2 - 4 \). This is in the vertex form of a quadratic equation, which is \( y = (x-h)^2 + k \).

In the vertex form \( y = (x-h)^2 + k \), the vertex is \((h, k)\). By comparing the given equation to the standard form, we identify \( h = -5 \) and \( k = -4 \).

Final Answer