The problem states this is a 45-45-90 triangle. This means it's a right isosceles triangle.
In a 45-45-90 triangle, the two legs are congruent, and the hypotenuse is $\sqrt{2}$ times the length of a leg.
Here, the leg has length $\sqrt{14}$. Thus, the hypotenuse $x = \sqrt{14} \times \sqrt{2} = \sqrt{14 \times 2} = \sqrt{28} = \sqrt{4 \times 7} = 2\sqrt{7}$.
$2\sqrt{7}$
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