Questions: Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given questions. Listed below are the highest amounts of net worth (in millions of dollars) of all celebrities. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? 265, 200, 185, 165, 155, 155, 150, 150, 150, 150 a. Find the mean. The mean is million. (Type an integer or a decimal rounded to one decimal place as needed.)

Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given questions. Listed below are the highest amounts of net worth (in millions of dollars) of all celebrities. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? 265, 200, 185, 165, 155, 155, 150, 150, 150, 150 a. Find the mean. The mean is million. (Type an integer or a decimal rounded to one decimal place as needed.)
Transcript text: Find the (a) mean, (b) median, (c) mode, and (d) midrange for the data and then (e) answer the given questions. Listed below are the highest amounts of net worth (in millions of dollars) of all celebrities. What do the results tell us about the population of all celebrities? Based on the nature of the amounts, what can be inferred about their precision? 265, 200, 185, 165, 155, 155, 150, 150, 150, 150 a. Find the mean. The mean is $\$$ $\square$ million. (Type an integer or a decimal rounded to one decimal place as needed.)
failed

Solution

failed
failed

Solution Steps

Step 1: Calculate the Mean

To find the mean of the given data, we use the formula:

\[ \mu = \frac{\sum_{i=1}^N x_i}{N} \]

where \( N \) is the number of data points and \( x_i \) are the individual data values. For the provided data:

\[ \sum_{i=1}^{10} x_i = 265 + 200 + 185 + 165 + 155 + 155 + 150 + 150 + 150 + 150 = 1725 \]

Thus, the mean is calculated as:

\[ \mu = \frac{1725}{10} = 172.5 \]

Step 2: Interpret the Results

The mean net worth of the celebrities is \( \mu = 172.5 \) million dollars. This value represents the average wealth among the selected celebrities, indicating that while some individuals have significantly higher net worths, the average remains at \( 172.5 \) million.

Final Answer

The mean is \(\boxed{172.5}\) million.

Was this solution helpful?
failed
Unhelpful
failed
Helpful

Questions asked by other users

failedAnswered
Identify scale factor in scale drawings Figure B is a scaled copy of Figure A. What is the scale factor from Figure A to Figure B?
failedAnswered
How does transcription differ in eukaryotes and bacteria? Eukaryotic transcription does not require a promoter sequence. Eukaryotic transcription requires more proteins. The initiation stage of transcription is more complex in bacteria. Bacteria have more types of RNA polymerase.
failedAnswered
Question 15° 2 Points Usually consisting of a triad or larger, a temporary or permanent alliance geared toward a common goal is a A secondary group (B) coalition (C) groupthink (D) dyad
failedAnswered
Answer the quiz question. Lower your LabPad and take a look at the PC screen again to explore the graph. A regression formula is obtained from the standard curve. This formula describes the relationship between concentration and absorbance data. We can use this regression formula to calculate the concentration of unknown samples. In this case, which regression type best describes our absorbance data? a) Linear b) Exponential c) Power d) log -log
failedAnswered
What does the saying "the dose makes the poison" mean? What matters is the amount of a toxic substance present; whether or not we are exposed to the toxin is not relevant. Any amount of a dangerous substance is unacceptable and counting the numbers of compounds detected is a reliable way to establish danger. Most substances are toxic at some level of exposure depending on the substance and the nature of the exposure. All substances have equivalent potential for harm, so exposure to any of them is risky.