Questions: Construct a 95% confidence interval estimate for the difference between two population means based on the following information:
Population 1 Population 2
barx1=355 barx2=320
sigma1=50 sigma2=40
n1=50 n2=80
Transcript text: Construct a $95 \%$ confidence interval estimate for the difference between two population means based on the following information:
\begin{tabular}{|c|c|}
\hline Population 1 & Population 2 \\
\hline $\bar{x}_{1}=355$ & $\bar{x}_{2}=320$ \\
\hline$\sigma_{1}=50$ & $\sigma_{2}=40$ \\
\hline$n_{1}=50$ & $n_{2}=80$ \\
\hline
\end{tabular}
Solution
Solution Steps
To construct a 95% confidence interval estimate for the difference between two population means, we can use the following steps:
Calculate the point estimate of the difference between the two means.
Determine the standard error of the difference between the two means.
Find the critical value for a 95% confidence level.
Construct the confidence interval using the point estimate, the critical value, and the standard error.
Step 1: Calculate the Point Estimate
The point estimate of the difference between the two population means is given by:
\[
\bar{x}_1 - \bar{x}_2 = 355 - 320 = 35
\]
Step 2: Determine the Standard Error
The standard error of the difference between the two means is calculated as:
\[
\text{SE} = \sqrt{\frac{\sigma_1^2}{n_1} + \frac{\sigma_2^2}{n_2}} = \sqrt{\frac{50^2}{50} + \frac{40^2}{80}} = \sqrt{50 + 20} = \sqrt{70} \approx 8.3666
\]
Step 3: Find the Critical Value
For a 95% confidence level, the critical value \( z_{\alpha/2} \) is:
\[
z_{\alpha/2} \approx 1.960
\]
Step 4: Construct the Confidence Interval
The margin of error (ME) is calculated as:
\[
\text{ME} = z_{\alpha/2} \times \text{SE} = 1.960 \times 8.3666 \approx 16.3982
\]
The confidence interval is then:
\[
(\bar{x}_1 - \bar{x}_2) \pm \text{ME} = 35 \pm 16.3982
\]
Final Answer
The 95% confidence interval estimate for the difference between the two population means is:
\[
\boxed{(18.6018, 51.3982)}
\]