Questions: Find the area of the figure. A=912 m^2 (Simplify your answer.)

Solution Steps

The given figure can be divided into a rectangle and a triangle. The rectangle is at the bottom, and the triangle is on top of the rectangle.

The dimensions of the rectangle are given as 48 meters (length) and 14 meters (height). \[ \text{Area of the rectangle} = \text{length} \times \text{height} = 48 \, \text{m} \times 14 \, \text{m} = 672 \, \text{m}^2 \]

The base of the triangle is the same as the length of the rectangle, which is 48 meters. The height of the triangle is given as 12 meters (26 meters total height minus 14 meters height of the rectangle). \[ \text{Area of the triangle} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 48 \, \text{m} \times 12 \, \text{m} = 288 \, \text{m}^2 \]

Add the area of the rectangle and the area of the triangle to find the total area of the figure. \[ \text{Total area} = 672 \, \text{m}^2 + 288 \, \text{m}^2 = 960 \, \text{m}^2 \]

Final Answer