Questions: 4x + 1/3 when x = 3/4

4x + 1/3 when x = 3/4
Transcript text: $4 x+\frac{1}{3}$ when $x=\frac{3}{4}$
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Solution

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Evaluate 4x+134x + \frac{1}{3} when x=34x = \frac{3}{4}.

Substitute x=34x = \frac{3}{4} into the expression.

4x+13=4⋅34+134x + \frac{1}{3} = 4 \cdot \frac{3}{4} + \frac{1}{3}.

Simplify the multiplication.

4⋅34=34 \cdot \frac{3}{4} = 3, so the expression becomes 3+133 + \frac{1}{3}.

Add the terms.

3+13=93+13=1033 + \frac{1}{3} = \frac{9}{3} + \frac{1}{3} = \frac{10}{3}.

103\boxed{\frac{10}{3}}

103\boxed{\frac{10}{3}}

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