Questions: Complete the description of the piecewise function graphed below.
I if -6 ≤ x ≤ -2
f(x)=1 if -2 < x ≤ 1
1 if 1 < x ≤ 6
Transcript text: Complete the description of the piecewise function graphed below.
I $\square$ if $-6 \leq x \leq-2$
$f(x)=1$ $\square$ if $-2
Solution
Solution Steps
Step 1: Find the equation for the first interval (-6 ≤ x ≤ -2)
The line segment connecting (-6, 1) and (-2, 4) has a slope of (4-1)/(-2 - -6) = 3/4. Using the point-slope form of a linear equation, we have y - 1 = (3/4)(x - -6), simplifying to y = (3/4)x + 11/2.
Step 2: Find the equation for the second interval (-2 < x ≤ 1)
The line segment is a horizontal line at y=4, hence the equation is y = 4. Note that x=-2 is excluded from this interval based on the open circle at x=-2.
Step 3: Find the equation for the third interval (1 < x ≤ 6)
The line segment connects (1, 4) and (6,-4). Its slope is (-4-4)/(6-1) = -8/5. Using point-slope form, we have y - 4 = (-8/5)(x-1). Simplifying, we get y = (-8/5)x + 28/5. Note that x=1 is excluded from this interval due to the open circle at x=1.
Final Answer:
f(x) = { (3/4)x + 11/2 if -6 ≤ x ≤ -2
{ 4 if -2 < x ≤ 1
{ (-8/5)x + 28/5 if 1 < x ≤ 6