Questions: To install OTTO (one sale, one must correctly solve 6 numbers from 1 through 65). The order in which the solution is made does not matter. How many different selections of 6 numbers from 1 through 65 are possible?
Transcript text: To install OTTO (one sale, one must correctly solve 6 numbers from 1 through 65). The order in which the solution is made does not matter. How many different selections of 6 numbers from 1 through 65 are possible?
Solution
Solution Steps
To determine the number of different selections of 6 numbers from 1 through 65, we need to calculate the number of combinations. This is a classic combinatorics problem where the order of selection does not matter. We use the combination formula, which is given by C(n, k) = n! / (k! * (n-k)!), where n is the total number of items to choose from, and k is the number of items to choose.
Step 1: Define the Problem
We need to find the number of different selections of 6 numbers from a set of 65 numbers. This is a combinatorial problem where the order of selection does not matter.
Step 2: Use the Combination Formula
The number of combinations of selecting \( k \) items from \( n \) items is given by the formula:
\[
C(n, k) = \frac{n!}{k!(n-k)!}
\]
In our case, \( n = 65 \) and \( k = 6 \).
Step 3: Calculate the Combinations
Substituting the values into the formula, we have:
\[
C(65, 6) = \frac{65!}{6!(65-6)!} = \frac{65!}{6! \cdot 59!}
\]
Calculating this gives us:
\[
C(65, 6) = 82598880
\]
Final Answer
The total number of different selections of 6 numbers from 1 through 65 is
\[
\boxed{82598880}
\]