Questions: Determine the truth value of the statement (p ∨ ¬q) ∧ r using the following conditions. a) p is true, q is false, and r is true. b) p is false, q is false, and r is false. a) If p is true, q is false, and r is true, what is the truth value of (p ∨ ¬q) ∧ r?

Determine the truth value of the statement (p ∨ ¬q) ∧ r using the following conditions.
a) p is true, q is false, and r is true.
b) p is false, q is false, and r is false.
a) If p is true, q is false, and r is true, what is the truth value of (p ∨ ¬q) ∧ r?
Transcript text: Determine the truth value of the statement $(p \vee \sim q) \wedge r$ using the following conditions. a) $p$ is true, $q$ is false, and $r$ is true. b) $p$ is false, $q$ is false, and $r$ is false. a) If $p$ is true, $q$ is false, and $r$ is true, what is the truth value of $(p \vee \sim q) \wedge r$ ?
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Solution

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Solution Steps

To determine the truth value of the statement \((p \vee \sim q) \wedge r\) under given conditions, we need to evaluate the logical expression step-by-step for each set of conditions.

  1. For condition (a): \(p\) is true, \(q\) is false, and \(r\) is true.

    • Evaluate \(\sim q\) (the negation of \(q\)).
    • Evaluate \(p \vee \sim q\) (the disjunction of \(p\) and \(\sim q\)).
    • Evaluate \((p \vee \sim q) \wedge r\) (the conjunction of the result from the previous step and \(r\)).
  2. For condition (b): \(p\) is false, \(q\) is false, and \(r\) is false.

    • Follow the same steps as in condition (a).
Step 1: Evaluate \(\sim q\) for Each Condition

For condition (a): \(q\) is false, so \(\sim q\) is true.

For condition (b): \(q\) is false, so \(\sim q\) is true.

Step 2: Evaluate \(p \vee \sim q\) for Each Condition

For condition (a): \(p\) is true and \(\sim q\) is true, so \(p \vee \sim q\) is true.

For condition (b): \(p\) is false and \(\sim q\) is true, so \(p \vee \sim q\) is true.

Step 3: Evaluate \((p \vee \sim q) \wedge r\) for Each Condition

For condition (a): \(p \vee \sim q\) is true and \(r\) is true, so \((p \vee \sim q) \wedge r\) is true.

For condition (b): \(p \vee \sim q\) is true but \(r\) is false, so \((p \vee \sim q) \wedge r\) is false.

Final Answer

For condition (a): \(\boxed{\text{True}}\)

For condition (b): \(\boxed{\text{False}}\)

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