To solve the given problems, we will use the provided function \( p(x) = 22,275(0.88)^x \) to calculate the price of the car for different values of \( x \). For parts (a) and (b), we will substitute \( x = 2 \) and \( x = 7 \) into the function to find the respective prices. For part (c), we will interpret the base 0.88 as the annual depreciation rate of the car's value.
To find the price of a car that is 2 years old, we substitute \( x = 2 \) into the price function \( p(x) = 22,275(0.88)^x \):
\[
p(2) = 22,275(0.88)^2 = 22,275 \times 0.7744 \approx 17,249.76
\]
Rounding to the nearest whole number, the price of a 2-year-old car is:
\[
\boxed{p(2) = 17250}
\]
Next, we calculate the price of a car that is 7 years old by substituting \( x = 7 \) into the same price function:
\[
p(7) = 22,275(0.88)^7 = 22,275 \times 0.5132 \approx 9,103.25
\]
Rounding to the nearest whole number, the price of a 7-year-old car is:
\[
\boxed{p(7) = 9103}
\]
The base \( 0.88 \) in the function represents the annual depreciation rate of the car's value. Specifically, it indicates that the car retains \( 88\% \) of its value each year, meaning it loses \( 12\% \) of its value annually.
- The price of a 2-year-old car is \( \boxed{17250} \).
- The price of a 7-year-old car is \( \boxed{9103} \).
- The base \( 0.88 \) signifies an annual depreciation rate of \( 12\% \).