Questions: Put the equation (y=4 x^2-7 x+5) in vertex form and state the values of (a, h) and (k). Enter the exact answers.
Vertex form: (y=)
(a=)
(h=)
(k=)
Transcript text: Put the equation $y=4 x^{2}-7 x+5$ in vertex form and state the values of $a, h$ and $k$. Enter the exact answers.
Vertex form: $y=$ $\square$
$a=$ $\square$
$h=$ $\square$
$k=$ $\square$
Solution
Solution Steps
To convert the quadratic equation \( y = 4x^2 - 7x + 5 \) into vertex form, we need to complete the square. The vertex form of a quadratic equation is \( y = a(x-h)^2 + k \), where \((h, k)\) is the vertex of the parabola. We will first factor out the coefficient of \( x^2 \) from the first two terms, then complete the square inside the parentheses, and finally adjust the constant term to maintain equality.
Step 1: Convert to Vertex Form
To convert the quadratic equation \( y = 4x^2 - 7x + 5 \) into vertex form, we complete the square. The vertex form is given by:
\[
y = a(x - h)^2 + k
\]
Step 2: Identify Coefficients
From the equation, we identify the coefficients:
\( a = 4 \)
\( b = -7 \)
\( c = 5 \)
Step 3: Calculate \( h \) and \( k \)
Using the formulas for \( h \) and \( k \):
\[
h = -\frac{b}{2a} = -\frac{-7}{2 \cdot 4} = \frac{7}{8} = 0.875
\]
\[
k = c - \frac{b^2}{4a} = 5 - \frac{(-7)^2}{4 \cdot 4} = 5 - \frac{49}{16} = 5 - 3.0625 = 1.9375
\]
Step 4: Write the Vertex Form
Substituting \( h \) and \( k \) back into the vertex form, we have:
\[
y = 4\left(x - 0.875\right)^2 + 1.9375
\]
Final Answer
The vertex form of the equation is \( y = 4\left(x - 0.875\right)^2 + 1.9375 \), with the values:
\( a = 4 \)
\( h = 0.875 \)
\( k = 1.9375 \)
Thus, the final answers are:
\[
\boxed{a = 4}
\]
\[
\boxed{h = 0.875}
\]
\[
\boxed{k = 1.9375}
\]