Questions: The middle term of the trinomial has been rewritten. Factor by grouping.
32 t^2 + 36 t + 9 = 32 t^2 + 24 t + 12 t + 9
Transcript text: The middle term of the trinomial has been rewritten. Factor by grouping.
\[
32 t^{2}+36 t+9=32 t^{2}+24 t+12 t+9
\]
Solution
Solution Steps
To factor the trinomial by grouping, we first rewrite the middle term as two separate terms, which has already been done in the problem. Next, we group the terms into two pairs and factor out the greatest common factor from each pair. Finally, we factor out the common binomial factor from the resulting expression.
Step 1: Rewrite the Expression
We start with the trinomial \( 32t^2 + 36t + 9 \). The middle term has been rewritten as \( 32t^2 + 24t + 12t + 9 \).
Step 2: Group the Terms
Next, we group the terms into two pairs:
\[
(32t^2 + 24t) + (12t + 9)
\]
Step 3: Factor Each Group
Now, we factor out the greatest common factor from each group:
\[
8t(4t + 3) + 3(4t + 3)
\]
Step 4: Factor Out the Common Binomial
We notice that \( (4t + 3) \) is a common factor:
\[
(4t + 3)(8t + 3)
\]
Final Answer
Thus, the factored form of the trinomial \( 32t^2 + 36t + 9 \) is:
\[
\boxed{(4t + 3)(8t + 3)}
\]