Questions: r(x)=-7x p(x)=x^2+8x q(x)=sqrt(9-x)

Transcript text: $r(x)=-7 x \quad p(x)=x^{2}+8 x \quad q(x)=\sqrt{9-x}$

Solution

Solution Steps

To solve the given functions $ r(x) = -7x $, $ p(x) = x^2 + 8x $, and $ q(x) = \sqrt{9 - x} $, we can define each function in Python and evaluate them for a given value of $ x $.

Step 1: Evaluate $ r(2) $

To evaluate the function $ r(x) = -7x $ at $ x = 2 $: \[ r(2) = -7 \cdot 2 = -14 \]

Step 2: Evaluate $ p(2) $

To evaluate the function $ p(x) = x^2 + 8x $ at $ x = 2 $: \[ p(2) = 2^2 + 8 \cdot 2 = 4 + 16 = 20 \]

Step 3: Evaluate $ q(2) $

To evaluate the function $ q(x) = \sqrt{9 - x} $ at $ x = 2 $: \[ q(2) = \sqrt{9 - 2} = \sqrt{7} \approx 2.6458 \]

Final Answer

The evaluations yield:

$ r(2) = -14 $
$ p(2) = 20 $
$ q(2) \approx 2.6458 $

Thus, the final answers are: \[ \boxed{r(2) = -14} \] \[ \boxed{p(2) = 20} \] \[ \boxed{q(2) \approx 2.6458} \]

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