Questions: George studied 1 / 4 hour on Monday and 3 / 8 hour on Tuesday. How long did he study altogether on both days?

George studied 1 / 4 hour on Monday and 3 / 8 hour on Tuesday. How long did he study altogether on both days?
Transcript text: George studied $1 / 4$ hour on Monday and $3 / 8$ hour on Tuesday. How long did he study altogether on both days?
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Solution

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Solution Steps

To find out how long George studied altogether on both days, we need to add the fractions representing the time he studied on Monday and Tuesday. The fractions have different denominators, so we will first find a common denominator, convert the fractions, and then add them together.

Step 1: Convert to a Common Denominator

To add the fractions \( \frac{1}{4} \) and \( \frac{3}{8} \), we first need to find a common denominator. The least common multiple of the denominators \( 4 \) and \( 8 \) is \( 8 \).

Step 2: Rewrite the Fractions

Next, we convert \( \frac{1}{4} \) to a fraction with a denominator of \( 8 \): \[ \frac{1}{4} = \frac{2}{8} \] Now we can rewrite the fractions: \[ \frac{2}{8} + \frac{3}{8} \]

Step 3: Add the Fractions

Now that both fractions have the same denominator, we can add them: \[ \frac{2}{8} + \frac{3}{8} = \frac{2 + 3}{8} = \frac{5}{8} \]

Final Answer

The total time George studied altogether on both days is \[ \boxed{\frac{5}{8}} \]

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