Questions: George studied 1 / 4 hour on Monday and 3 / 8 hour on Tuesday. How long did he study altogether on both days?
Transcript text: George studied $1 / 4$ hour on Monday and $3 / 8$ hour on Tuesday. How long did he study altogether on both days?
Solution
Solution Steps
To find out how long George studied altogether on both days, we need to add the fractions representing the time he studied on Monday and Tuesday. The fractions have different denominators, so we will first find a common denominator, convert the fractions, and then add them together.
Step 1: Convert to a Common Denominator
To add the fractions \( \frac{1}{4} \) and \( \frac{3}{8} \), we first need to find a common denominator. The least common multiple of the denominators \( 4 \) and \( 8 \) is \( 8 \).
Step 2: Rewrite the Fractions
Next, we convert \( \frac{1}{4} \) to a fraction with a denominator of \( 8 \):
\[
\frac{1}{4} = \frac{2}{8}
\]
Now we can rewrite the fractions:
\[
\frac{2}{8} + \frac{3}{8}
\]
Step 3: Add the Fractions
Now that both fractions have the same denominator, we can add them:
\[
\frac{2}{8} + \frac{3}{8} = \frac{2 + 3}{8} = \frac{5}{8}
\]
Final Answer
The total time George studied altogether on both days is
\[
\boxed{\frac{5}{8}}
\]