To solve the given expression, we need to follow these steps:
We start with the expression:
d3−a3d2−a2÷7d−7a7d+7a \frac{d^{3}-a^{3}}{d^{2}-a^{2}} \div \frac{7 d-7 a}{7 d+7 a} d2−a2d3−a3÷7d+7a7d−7a
First, we factor the numerator and denominator of the first fraction:
d3−a3=−(a−d)(a2+ad+d2) d^{3} - a^{3} = -(a - d)(a^{2} + ad + d^{2}) d3−a3=−(a−d)(a2+ad+d2)
d2−a2=−(a−d)(a+d) d^{2} - a^{2} = -(a - d)(a + d) d2−a2=−(a−d)(a+d)
Next, we factor the second fraction:
7(d−a)=−7(a−d) 7(d - a) = -7(a - d) 7(d−a)=−7(a−d)
7(d+a) 7(d + a) 7(d+a)
Now we rewrite the division of the two fractions as multiplication by the reciprocal:
−(a−d)(a2+ad+d2)−(a−d)(a+d)×7(d+a)−7(a−d) \frac{-(a - d)(a^{2} + ad + d^{2})}{-(a - d)(a + d)} \times \frac{7(d + a)}{-7(a - d)} −(a−d)(a+d)−(a−d)(a2+ad+d2)×−7(a−d)7(d+a)
We can simplify the expression by canceling out common factors:
=(a2+ad+d2)(a+d)×(d+a)(a−d) = \frac{(a^{2} + ad + d^{2})}{(a + d)} \times \frac{(d + a)}{(a - d)} =(a+d)(a2+ad+d2)×(a−d)(d+a)
This simplifies to:
=−(a2+ad+d2)(a−d) = \frac{-(a^{2} + ad + d^{2})}{(a - d)} =(a−d)−(a2+ad+d2)
Thus, the simplified expression is:
−(a2+ad+d2)(a−d) \boxed{\frac{-(a^{2} + ad + d^{2})}{(a - d)}} (a−d)−(a2+ad+d2)
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