Questions: Solid barium carbonate (BaCO3) decomposes into carbon dioxide gas and solid barium oxide. Write a balanced chemical equation for this reaction. BaCO3 → BaO + CO2

Solid barium carbonate (BaCO3) decomposes into carbon dioxide gas and solid barium oxide.
Write a balanced chemical equation for this reaction.
BaCO3 → BaO + CO2

Transcript text: Solid barium carbonate $\left(\mathrm{BaCO}_{3}\right)$ decomposes into carbon dioxide gas and solid barium oxide . Write a balanced chemical equation for this reaction. \[ \mathrm{BaCO}_{3} \rightarrow \mathrm{BaO}+\mathrm{CO}_{2} \]

Solution

Solution Steps

Step 1: Identify the Reactants and Products

The reaction involves the decomposition of solid barium carbonate ($\mathrm{BaCO}_{3}$) into carbon dioxide gas ($\mathrm{CO}_{2}$) and solid barium oxide ($\mathrm{BaO}$).

Step 2: Write the Unbalanced Chemical Equation

The unbalanced chemical equation for the decomposition reaction is: \[ \mathrm{BaCO}_{3} \rightarrow \mathrm{BaO} + \mathrm{CO}_{2} \]

Step 3: Balance the Chemical Equation

To balance the chemical equation, ensure that the number of each type of atom on the reactant side is equal to the number on the product side. In this case, the equation is already balanced as there is one barium (Ba), one carbon (C), and three oxygen (O) atoms on both sides of the equation.

Final Answer

The balanced chemical equation for the decomposition of barium carbonate is: \[ \boxed{\mathrm{BaCO}_{3} \rightarrow \mathrm{BaO} + \mathrm{CO}_{2}} \]

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