Questions: Solve the following equation for (x).
[
frac3x+3-frac2x-1=-frac1x^2+2 x-3
]
Provide your answer below:
[
x=
]
Transcript text: Solve the following equation for $x$.
\[
\frac{3}{x+3}-\frac{2}{x-1}=-\frac{1}{x^{2}+2 x-3}
\]
Provide your answer below:
\[
x=
\]
Solution
Solution Steps
To solve the given equation for \( x \), we need to find a common denominator for the fractions, combine them, and then solve the resulting polynomial equation. The common denominator will be \( (x+3)(x-1) \). After combining the fractions, we will set the numerator equal to zero and solve for \( x \).
Step 1: Identify the Common Denominator
To solve the equation
\[
\frac{3}{x+3} - \frac{2}{x-1} = -\frac{1}{x^2 + 2x - 3},
\]
we first identify the common denominator. The denominator \( x^2 + 2x - 3 \) can be factored as \( (x+3)(x-1) \).
Step 2: Combine the Fractions
Rewrite the equation with the common denominator:
\[
\frac{3(x-1) - 2(x+3)}{(x+3)(x-1)} = -\frac{1}{(x+3)(x-1)}.
\]
Simplify the numerator:
\[
3(x-1) - 2(x+3) = 3x - 3 - 2x - 6 = x - 9.
\]
Thus, the equation becomes:
\[
\frac{x - 9}{(x+3)(x-1)} = -\frac{1}{(x+3)(x-1)}.
\]
Step 3: Set the Numerators Equal
Since the denominators are the same, we set the numerators equal:
\[
x - 9 = -1.
\]
Step 4: Solve for \( x \)
Solve the equation:
\[
x - 9 = -1 \implies x = 8.
\]