Questions: The molar mass of calcium hydroide is 74.1 g / mol 38.1 g / mol 114 g / mol 73.1 g / mol 63.55+57.1 g / mol

The molar mass of calcium hydroide is 
74.1 g / mol
38.1 g / mol
114 g / mol
73.1 g / mol
63.55+57.1 g / mol
Transcript text: The molar mass of calcium hydroxide is $\qquad$ $74.1 \mathrm{~g} / \mathrm{mol}$ $38.1 \mathrm{~g} / \mathrm{mol}$ $114 \mathrm{~g} / \mathrm{mol}$ $73.1 \mathrm{~g} / \mathrm{mol}$ $63.55+57.1 \mathrm{~g} / \mathrm{mol}$
failed

Solution

failed
failed

Solution Steps

Step 1: Identify the Chemical Formula

The chemical formula for calcium hydroxide is \( \text{Ca(OH)}_2 \).

Step 2: Determine the Atomic Masses
  • The atomic mass of calcium (Ca) is approximately \( 40.08 \, \text{g/mol} \).
  • The atomic mass of oxygen (O) is approximately \( 16.00 \, \text{g/mol} \).
  • The atomic mass of hydrogen (H) is approximately \( 1.008 \, \text{g/mol} \).
Step 3: Calculate the Molar Mass

The molar mass of calcium hydroxide \( \text{Ca(OH)}_2 \) is calculated as follows: \[ \text{Molar mass of } \text{Ca(OH)}_2 = 40.08 + 2 \times (16.00 + 1.008) \] \[ = 40.08 + 2 \times 17.008 \] \[ = 40.08 + 34.016 \] \[ = 74.096 \, \text{g/mol} \]

Step 4: Round to Appropriate Significant Digits

Rounding \( 74.096 \, \text{g/mol} \) to four significant digits gives \( 74.10 \, \text{g/mol} \).

Final Answer

\[ \boxed{74.1 \, \text{g/mol}} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful