Questions: Factor the binomial completely. s^3 - 729 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. s^3 - 729 = (Factor completely.) B. The binomial is prime.

Factor the binomial completely.

s^3 - 729

Select the correct choice below and, if necessary, fill in the answer box to complete your choice.
A. s^3 - 729 = (Factor completely.)
B. The binomial is prime.
Transcript text: possible Factor the binomial completely. \[ s^{3}-729 \] Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. $s^{3}-729=$ $\square$ (Factor completely.) B. The binomial is prime. Time Remaining: 01:30:30 Next
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Solution

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Solution Steps

To factor the binomial \( s^3 - 729 \) completely, we recognize that it is a difference of cubes. The difference of cubes formula is given by: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \] Here, \( s^3 - 729 \) can be written as \( s^3 - 9^3 \).

Solution Approach
  1. Identify \( a \) and \( b \) such that \( a^3 = s^3 \) and \( b^3 = 729 \).
  2. Apply the difference of cubes formula.
Step 1: Identify the Difference of Cubes

The expression \( s^3 - 729 \) can be recognized as a difference of cubes, where \( a = s \) and \( b = 9 \) since \( 729 = 9^3 \).

Step 2: Apply the Difference of Cubes Formula

Using the difference of cubes formula: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \] we substitute \( a \) and \( b \): \[ s^3 - 9^3 = (s - 9)(s^2 + 9s + 81) \]

Final Answer

Thus, the complete factorization of the binomial \( s^3 - 729 \) is: \[ \boxed{(s - 9)(s^2 + 9s + 81)} \]

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