Questions: Determine the end behavior, y-intercept, x-intercept(s) and multiplicities for the polynomial below, and then sketch a graph. f(x)=-3 x(x-1)^3(x+2)^2

Determine the end behavior, y-intercept, x-intercept(s) and multiplicities for the polynomial below, and then sketch a graph.
f(x)=-3 x(x-1)^3(x+2)^2
Transcript text: 5. Determine the end behavior, $y$-intercept, $x$-intercept(s) and multiplicities for the polynomial below, and then sketch a graph. \[ f(x)=-3 x(x-1)^{3}(x+2)^{2} \]
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Solution

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Solution Steps

Step 1: Determine the End Behavior

The polynomial function is \( f(x) = -3x(x-1)^3(x+2)^2 \). The degree of the polynomial is the sum of the exponents: \(1 + 3 + 2 = 6\). Since the leading term is negative, the end behavior is:

  • As \( x \to \infty \), \( f(x) \to -\infty \).
  • As \( x \to -\infty \), \( f(x) \to -\infty \).
Step 2: Find the \( y \)-Intercept

The \( y \)-intercept is found by evaluating \( f(0) \): \[ f(0) = -3 \cdot 0 \cdot (0-1)^3 \cdot (0+2)^2 = 0 \] Thus, the \( y \)-intercept is \( (0, 0) \).

Step 3: Find the \( x \)-Intercept(s) and Multiplicities

The \( x \)-intercepts occur where \( f(x) = 0 \): \[ -3x(x-1)^3(x+2)^2 = 0 \] The solutions are:

  • \( x = 0 \) with multiplicity 1
  • \( x = 1 \) with multiplicity 3
  • \( x = -2 \) with multiplicity 2

Final Answer

  • End behavior: As \( x \to \infty \), \( f(x) \to -\infty \); as \( x \to -\infty \), \( f(x) \to -\infty \).
  • \( y \)-intercept: \( (0, 0) \)
  • \( x \)-intercepts: \( x = 0 \) (multiplicity 1), \( x = 1 \) (multiplicity 3), \( x = -2 \) (multiplicity 2)

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