Questions: What are the ordered pair solutions for this system of equations?
y=x^2-2x+3
y=-2x+12
First, set the equations equal to each other and move everything to one side.
A: x^2+9=0
B: x^2-4x+15=0
C: x^2-9=0
D: x^2+15=0
What are the ordered pair solutions for this system of equations?
y=x^2-2x+3
y=-2x+12
First, set the equations equal to each other and move everything to one side.
A: x^2+9=0
B: x^2-4x+15=0
C: x^2-9=0
D: x^2+15=0
Solution
Solution Steps
To find the ordered pair solutions for the given system of equations, we need to set the two equations equal to each other and solve for \( x \). Once we have the values of \( x \), we can substitute them back into either equation to find the corresponding \( y \) values. This will give us the ordered pairs that satisfy both equations.
Step 1: Set the Equations Equal to Each Other
To find the points of intersection, set the two equations equal to each other:
\[
x^2 - 2x + 3 = -2x + 12
\]
Step 2: Simplify and Solve for \( x \)
Rearrange the equation to bring all terms to one side:
\[
x^2 - 2x + 3 + 2x - 12 = 0 \implies x^2 - 9 = 0
\]
Solve for \( x \) by factoring:
\[
(x - 3)(x + 3) = 0
\]
Thus, the solutions for \( x \) are:
\[
x = 3 \quad \text{and} \quad x = -3
\]
Step 3: Substitute \( x \) Values to Find Corresponding \( y \) Values
Substitute \( x = 3 \) into the second equation \( y = -2x + 12 \):
\[
y = -2(3) + 12 = 6
\]
Substitute \( x = -3 \) into the second equation \( y = -2x + 12 \):
\[
y = -2(-3) + 12 = 18
\]
Final Answer
The ordered pair solutions for the system of equations are:
\[
\boxed{(3, 6)} \quad \text{and} \quad \boxed{(-3, 18)}
\]