Questions: What are the ordered pair solutions for this system of equations? y=x^2-2x+3 y=-2x+12 First, set the equations equal to each other and move everything to one side. A: x^2+9=0 B: x^2-4x+15=0 C: x^2-9=0 D: x^2+15=0

What are the ordered pair solutions for this system of equations? y=x^2-2x+3 y=-2x+12 First, set the equations equal to each other and move everything to one side. A: x^2+9=0 B: x^2-4x+15=0 C: x^2-9=0 D: x^2+15=0

Solution

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Solution Steps

To find the ordered pair solutions for the given system of equations, we need to set the two equations equal to each other and solve for \( x \). Once we have the values of \( x \), we can substitute them back into either equation to find the corresponding \( y \) values. This will give us the ordered pairs that satisfy both equations.

Step 1: Set the Equations Equal to Each Other

To find the points of intersection, set the two equations equal to each other: \[ x^2 - 2x + 3 = -2x + 12 \]

Step 2: Simplify and Solve for \( x \)

Rearrange the equation to bring all terms to one side: \[ x^2 - 2x + 3 + 2x - 12 = 0 \implies x^2 - 9 = 0 \] Solve for \( x \) by factoring: \[ (x - 3)(x + 3) = 0 \] Thus, the solutions for \( x \) are: \[ x = 3 \quad \text{and} \quad x = -3 \]

Step 3: Substitute \( x \) Values to Find Corresponding \( y \) Values

Substitute \( x = 3 \) into the second equation \( y = -2x + 12 \): \[ y = -2(3) + 12 = 6 \] Substitute \( x = -3 \) into the second equation \( y = -2x + 12 \): \[ y = -2(-3) + 12 = 18 \]

Final Answer

The ordered pair solutions for the system of equations are: \[ \boxed{(3, 6)} \quad \text{and} \quad \boxed{(-3, 18)} \]

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