Questions: A normal population has a mean of 75 and standard deviation of 5. You select random samples of 40.
Required:
a. Apply the central limit theorem to describe the sampling distribution of the sample mean with n=40. What condition is necessary to apply the central limit theorem?
b. What is the standard error of the sampling distribution of sample means?
Note: Round your answer to 2 decimal places.
c. What is the probability that a sample mean is less than 74 ?
Note: Round z-value to 2 decimal places and final answer to 4 decimal places.
Transcript text: A normal population has a mean of $\$ 75$ and standard deviation of $\$ 5$. You select random samples of 40.
Required:
a. Apply the central limit theorem to describe the sampling distribution of the sample mean with $n=40$. What condition is necessary to apply the central limit theorem?
b. What is the standard error of the sampling distribution of sample means?
Note: Round your answer to 2 decimal places.
c. What is the probability that a sample mean is less than $\$ 74$ ?
Note: Round $z$-value to 2 decimal places and final answer to 4 decimal places.
Solution
Solution Steps
Step 1: Central Limit Theorem Application
According to the Central Limit Theorem, the sampling distribution of the sample mean will be approximately normal if the sample size \( n \) is sufficiently large (typically \( n \geq 30 \)). In this case, since \( n = 40 \), we can apply the theorem, and the sampling distribution of the sample mean will be normal.
Step 2: Standard Error Calculation
The standard error (SE) of the sampling distribution of the sample mean is calculated using the formula:
\[
SE = \frac{\sigma}{\sqrt{n}}
\]
where \( \sigma = 5 \) (the population standard deviation) and \( n = 40 \). Thus,
\[
SE = \frac{5}{\sqrt{40}} \approx 0.79
\]
Step 3: Probability Calculation
To find the probability that the sample mean is less than \( 74 \), we first calculate the Z-score for \( 74 \):