Questions: Solve the following equation for x. 124 = 4 e^(4x-2) Note: Round your answer to three decimal digits (the nearest thousandth).

Solve the following equation for x.
124 = 4 e^(4x-2)
Note: Round your answer to three decimal digits (the nearest thousandth).
Transcript text: e - College Algebra- 1 Mathematics | Michigan State WeBWork : -- webwork.math.msu.edu/webwork2/mth_103_fs24_2/Hw19-Obj-C4/9/?effe TATE I T Y Department of Mathematics Grades Course Help Hw19-Obj-C4: Problem 9 Problem Value: 1 point(s). Problem Score: 0\%. Attempts ReI (1 point) Solve the following equation for $x$. \[ 124=4 e^{4 x-2} \] $\square$ Note: Round your answer to three decimal digits (the nearest tho Help Entering Answers Preview My Answers Submit Answers Page generated at 10 WeBWorK © 1996-2019| theme: math4-msu| ww_version Search
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Solution

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Solution Steps

Solution Approach

To solve the equation \(124 = 4e^{4x-2}\) for \(x\), follow these steps:

  1. Divide both sides of the equation by 4 to isolate the exponential term.
  2. Take the natural logarithm (ln) of both sides to solve for the exponent.
  3. Rearrange the equation to solve for \(x\).
  4. Round the result to three decimal places.
Step 1: Isolate the Exponential Term

Starting with the equation: \[ 124 = 4e^{4x - 2} \] we divide both sides by 4: \[ 31 = e^{4x - 2} \]

Step 2: Take the Natural Logarithm

Next, we take the natural logarithm of both sides: \[ \ln(31) = 4x - 2 \]

Step 3: Solve for \(x\)

Rearranging the equation to solve for \(x\): \[ 4x = \ln(31) + 2 \] \[ x = \frac{\ln(31) + 2}{4} \] Calculating the value gives: \[ x \approx \frac{3.4339872044851463 + 2}{4} \approx 1.3584968011212866 \] Rounding to three decimal places, we find: \[ x \approx 1.358 \]

Final Answer

\[ \boxed{x = 1.358} \]

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