Questions: Use the prime factorization to group the factors and write as a product of two factors.
-6 k^10=(-1 cdot 3 cdot k cdot k cdot k cdot k cdot k cdot k cdot k) cdot(2 cdot k cdot k cdot k)
-6 k^10=-3 k^7(square)
(Type your answer using exponential notation.)
Transcript text: Use the prime factorization to group the factors and write as a product of two factors.
\[
\begin{array}{l}
-6 k^{10}=(-1 \cdot 3 \cdot k \cdot k \cdot k \cdot k \cdot k \cdot k \cdot k) \cdot(2 \cdot k \cdot k \cdot k) \\
-6 k^{10}=-3 k^{7}(\square)
\end{array}
\]
(Type your answer using exponential notation.)
Solution
Solution Steps
To solve this problem, we need to express \(-6k^{10}\) as a product of two factors using its prime factorization. We start by breaking down \(-6k^{10}\) into its prime factors and then group them into two separate products. The first factor is given as \(-3k^7\), and we need to determine the second factor by dividing the original expression by the first factor.
Step 1: Prime Factorization of \(-6k^{10}\)
We start with the expression:
\[
-6k^{10} = -1 \cdot 2 \cdot 3 \cdot k^{10}
\]
This can be rewritten as:
\[
-6k^{10} = (-3k^7) \cdot (2k^3)
\]
Step 2: Identifying the Factors
From the prime factorization, we can identify the two factors:
The first factor is given as:
\[
-3k^7
\]
The second factor, calculated from the division of the original expression by the first factor, is:
\[
2k^3
\]
Step 3: Writing the Final Expression
Thus, we can express \(-6k^{10}\) as a product of the two factors:
\[
-6k^{10} = (-3k^7) \cdot (2k^3)
\]
Final Answer
The second factor is \(2k^3\), so the complete expression is:
\[
\boxed{2k^3}
\]