Questions: Find the derivative of (0.4/(x^(1/4)) - 3.8x^(-4) + 2x) with respect to x.

Find the derivative of (0.4/(x^(1/4)) - 3.8x^(-4) + 2x) with respect to x.
Transcript text: Find $\frac{d}{d x}\left(\frac{0.4}{\sqrt[4]{x}}-3.8 x^{-4}+2 x\right)$.
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Solution

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Solution Steps

To find the derivative of the given function, we will apply the power rule for differentiation. The function is a combination of terms with different powers of \(x\). We will differentiate each term separately and then combine the results.

Step 1: Differentiate Each Term

To find the derivative of the function \( f(x) = \frac{0.4}{\sqrt[4]{x}} - 3.8 x^{-4} + 2x \), we differentiate each term separately using the power rule.

  1. The derivative of \( \frac{0.4}{\sqrt[4]{x}} \) can be rewritten as \( 0.4 x^{-1/4} \). Differentiating this term gives: \[ \frac{d}{dx}\left(0.4 x^{-1/4}\right) = 0.4 \times \left(-\frac{1}{4}\right) x^{-5/4} = -0.1 x^{-5/4} \]

  2. The derivative of \( -3.8 x^{-4} \) is: \[ \frac{d}{dx}\left(-3.8 x^{-4}\right) = -3.8 \times (-4) x^{-5} = 15.2 x^{-5} \]

  3. The derivative of \( 2x \) is: \[ \frac{d}{dx}(2x) = 2 \]

Step 2: Combine the Derivatives

Combine the derivatives of each term to find the derivative of the entire function: \[ f'(x) = -0.1 x^{-5/4} + 15.2 x^{-5} + 2 \]

Final Answer

\(\boxed{f'(x) = -0.1 x^{-5/4} + 15.2 x^{-5} + 2}\)

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