Questions: Consider the function y(t)=-5+2 cos (πt/3) a) Find the period. 1. 3 2. 6 3. 3/π 4. 2 5. 6/π 6. None of these

Consider the function
y(t)=-5+2 cos (πt/3)
a) Find the period.
1. 3
2. 6
3. 3/π
4. 2
5. 6/π
6. None of these
Transcript text: Consider the function \[ y(t)=-5+2 \cos \left(\frac{\pi t}{3}\right) \] a) Find the period. 1. 3 2. 6 3. $\frac{3}{\pi}$ 4. 2 5. $\frac{6}{\pi}$ 6. None of these
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Solution

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Solution Steps

To find the period of the function \( y(t) = -5 + 2 \cos \left(\frac{\pi t}{3}\right) \), we need to determine the period of the cosine function inside it. The general form of a cosine function is \( \cos(bt) \), where the period is given by \( \frac{2\pi}{b} \). In this case, \( b = \frac{\pi}{3} \).

Solution Approach
  1. Identify the coefficient \( b \) inside the cosine function.
  2. Use the formula for the period of a cosine function, \( \frac{2\pi}{b} \).
Step 1: Identify the Coefficient

The function given is

\[ y(t) = -5 + 2 \cos \left(\frac{\pi t}{3}\right) \]

In this function, the coefficient \( b \) inside the cosine is

\[ b = \frac{\pi}{3} \]

Step 2: Calculate the Period

The period \( T \) of a cosine function is calculated using the formula

\[ T = \frac{2\pi}{b} \]

Substituting the value of \( b \):

\[ T = \frac{2\pi}{\frac{\pi}{3}} = 2\pi \cdot \frac{3}{\pi} = 6 \]

Final Answer

The period of the function is

\[ \boxed{6} \]

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