Questions: Write the expression as a logarithm of a single expression.
[ 7 ln x-frac13 ln y ]
[ 7 ln x-frac13 ln y= ]
Transcript text: Write the expression as a logarithm of a single expression.
\[
7 \ln x-\frac{1}{3} \ln y
\]
\[
7 \ln x-\frac{1}{3} \ln y=
\]
$\square$
Solution
Solution Steps
Step 1: Apply the logarithm power rule
The logarithm power rule states that \( a \ln b = \ln b^a \). Apply this rule to both terms in the expression:
\[
7 \ln x = \ln x^7
\]
\[
\frac{1}{3} \ln y = \ln y^{1/3}
\]
Step 2: Rewrite the expression using the logarithm subtraction rule
The logarithm subtraction rule states that \( \ln a - \ln b = \ln \left( \frac{a}{b} \right) \). Apply this rule to the expression:
\[
7 \ln x - \frac{1}{3} \ln y = \ln x^7 - \ln y^{1/3} = \ln \left( \frac{x^7}{y^{1/3}} \right)
\]
Final Answer
The expression \( 7 \ln x - \frac{1}{3} \ln y \) as a logarithm of a single expression is:
\[
\boxed{\ln \left( \frac{x^7}{y^{1/3}} \right)}
\]