Questions: Write the expression as a logarithm of a single expression. [ 7 ln x-frac13 ln y ] [ 7 ln x-frac13 ln y= ]

Write the expression as a logarithm of a single expression.
[ 7 ln x-frac13 ln y ]
[ 7 ln x-frac13 ln y= ]
Transcript text: Write the expression as a logarithm of a single expression. \[ 7 \ln x-\frac{1}{3} \ln y \] \[ 7 \ln x-\frac{1}{3} \ln y= \] $\square$
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Solution

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Solution Steps

Step 1: Apply the logarithm power rule

The logarithm power rule states that \( a \ln b = \ln b^a \). Apply this rule to both terms in the expression: \[ 7 \ln x = \ln x^7 \] \[ \frac{1}{3} \ln y = \ln y^{1/3} \]

Step 2: Rewrite the expression using the logarithm subtraction rule

The logarithm subtraction rule states that \( \ln a - \ln b = \ln \left( \frac{a}{b} \right) \). Apply this rule to the expression: \[ 7 \ln x - \frac{1}{3} \ln y = \ln x^7 - \ln y^{1/3} = \ln \left( \frac{x^7}{y^{1/3}} \right) \]

Final Answer

The expression \( 7 \ln x - \frac{1}{3} \ln y \) as a logarithm of a single expression is: \[ \boxed{\ln \left( \frac{x^7}{y^{1/3}} \right)} \]

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