Questions: Find the distance between the points (8,-2) and (7,-1). 4 unit(s) sqrt(7) unit(s) 1 unit(s) sqrt(2) unit(s)

Find the distance between the points (8,-2) and (7,-1).
4 unit(s)
sqrt(7) unit(s)
1 unit(s)
sqrt(2) unit(s)
Transcript text: Find the distance between the points $(8,-2)$ and $(7,-1)$. 4 unit(s) $\sqrt{7}$ unit(s) 1 unit(s) $\sqrt{2}$ unit(s)
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Solution

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Solution Steps

To find the distance between two points \((x_1, y_1)\) and \((x_2, y_2)\) in a 2D plane, we use the distance formula: \(\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\). This formula is derived from the Pythagorean theorem.

Step 1: Identify the Points

We are given two points in the Cartesian plane: \[ (x_1, y_1) = (8, -2) \quad \text{and} \quad (x_2, y_2) = (7, -1). \]

Step 2: Apply the Distance Formula

To find the distance \(d\) between the two points, we use the distance formula: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}. \]

Step 3: Calculate the Differences

First, we calculate the differences: \[ x_2 - x_1 = 7 - 8 = -1, \] \[ y_2 - y_1 = -1 - (-2) = 1. \]

Step 4: Substitute and Simplify

Now we substitute these differences into the distance formula: \[ d = \sqrt{(-1)^2 + (1)^2} = \sqrt{1 + 1} = \sqrt{2}. \]

Final Answer

The distance between the points \((8, -2)\) and \((7, -1)\) is \[ \boxed{d = \sqrt{2}}. \]

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