Questions: Properties of Sound Waves Factors Affecting Intensity Use the drop-down menus to complete each statement. When the amplitude of a wave triples, the intensity changes by a factor of When the amplitude of a wave is cut in half, the intensity changes by a factor of When the distance between the source and your ear is ten times farther away, the intensity changes by a factor of When the distance between the source and your ear is reduced by 1 / 3, the intensity changes by a factor of

When the amplitude of a wave triples, the intensity changes by a factor of

Understanding the relationship between amplitude and intensity

The intensity of a wave is proportional to the square of its amplitude. Therefore, if the amplitude triples, the intensity changes by a factor of \(3^2\).

Calculating the factor

The factor is \(3^2 = 9\).

\(\boxed{9}\)

When the amplitude of a wave is cut in half, the intensity changes by a factor of

Understanding the relationship between amplitude and intensity

The intensity of a wave is proportional to the square of its amplitude. Therefore, if the amplitude is cut in half, the intensity changes by a factor of \((\frac{1}{2})^2\).

Calculating the factor

The factor is \((\frac{1}{2})^2 = \frac{1}{4}\).

\(\boxed{\frac{1}{4}}\)

When the distance between the source and your ear is ten times farther away, the intensity changes by a factor of

Understanding the relationship between distance and intensity

The intensity of a wave is inversely proportional to the square of the distance from the source. Therefore, if the distance is increased by a factor of 10, the intensity changes by a factor of \(\frac{1}{10^2}\).

Calculating the factor

The factor is \(\frac{1}{10^2} = \frac{1}{100}\).

\(\boxed{\frac{1}{100}}\)

When the distance between the source and your ear is reduced by \(\frac{1}{3}\), the intensity changes by a factor of

Understanding the relationship between distance and intensity

The intensity of a wave is inversely proportional to the square of the distance from the source. If the distance is reduced by \(\frac{1}{3}\), it means the new distance is \(\frac{2}{3}\) of the original. The intensity changes by a factor of \(\left(\frac{1}{\frac{2}{3}}\right)^2\).

Calculating the factor

The factor is \(\left(\frac{3}{2}\right)^2 = \frac{9}{4}\).

\(\boxed{\frac{9}{4}}\)

\(\boxed{9}\)
\(\boxed{\frac{1}{4}}\)
\(\boxed{\frac{1}{100}}\)
\(\boxed{\frac{9}{4}}\)