Questions: Chapter 6 HW (Part 1) - Sections 6.1-6.5 Question 2 of 15 (2 points) I Question Attempt: 1 of 3 The balanced equation for the dissolving of aluminum nitrite in water is: Al(NO2)3(s) -> H2O -> Al^3+(aq) + 3 NO2^-(aq) Part 1 of 2 How many Al^3+(aq) ions form for each Al(NO2)3 formula unit that dissolves? Part 2 of 2 How many moles of NO2^-(aq) form for each mole of Al(NO2)3 that dissolves?

Chapter 6 HW (Part 1) - Sections 6.1-6.5
Question 2 of 15 (2 points) I Question Attempt: 1 of 3

The balanced equation for the dissolving of aluminum nitrite in water is:
Al(NO2)3(s) -> H2O -> Al^3+(aq) + 3 NO2^-(aq)

Part 1 of 2

How many Al^3+(aq) ions form for each Al(NO2)3 formula unit that dissolves?

Part 2 of 2

How many moles of NO2^-(aq) form for each mole of Al(NO2)3 that dissolves?

Transcript text: Chapter 6 HW (Part 1) - Sections 6.1-6.5 Question 2 of 15 (2 points) I Question Attempt: 1 of 3 The balanced equation for the dissolving of aluminum nitrite in water is: \[ \mathrm{Al}\left(\mathrm{NO}_{2}\right)_{3}(s) \xrightarrow{\mathrm{H}_{2} \mathrm{O}} \mathrm{Al}^{3+}(a q)+3 \mathrm{NO}_{2}^{-}(a q) \] Part 1 of 2 How many $\mathrm{Al}^{3+}(\mathrm{aq})$ ions form for each $\mathrm{Al}\left(\mathrm{NO}_{2}\right)_{3}$ formula unit that dissolves? $\square$ $\mathrm{Al}^{3+}(a q)$ ion(s) $\square$ Part 2 of 2 How many moles of $\mathrm{NO}_{2}^{-}(\mathrm{aq})$ form for each mole of $\mathrm{Al}\left(\mathrm{NO}_{2}\right)_{3}$ that dissolves? $\square$ mole(s) of $\mathrm{NO}_{2}^{-}(\mathrm{aq})$ $\square$

Solution

Solution Steps

Step 1: Understanding the Dissolution Reaction

The balanced chemical equation for the dissolution of aluminum nitrite in water is given as:

\[ \mathrm{Al}\left(\mathrm{NO}_{2}\right)_{3}(s) \xrightarrow{\mathrm{H}_{2} \mathrm{O}} \mathrm{Al}^{3+}(a q)+3 \mathrm{NO}_{2}^{-}(a q) \]

This equation shows that one formula unit of aluminum nitrite dissociates into one aluminum ion ($\mathrm{Al}^{3+}$) and three nitrite ions ($\mathrm{NO}_{2}^{-}$).

Step 2: Determining the Number of $\mathrm{Al}^{3+}$ Ions

For each formula unit of $\mathrm{Al}\left(\mathrm{NO}_{2}\right)_{3}$ that dissolves, one $\mathrm{Al}^{3+}$ ion is produced. This is directly indicated by the stoichiometry of the balanced equation.

Step 3: Determining the Moles of $\mathrm{NO}_{2}^{-}$ Ions

For each mole of $\mathrm{Al}\left(\mathrm{NO}_{2}\right)_{3}$ that dissolves, three moles of $\mathrm{NO}_{2}^{-}$ ions are produced. This is also indicated by the stoichiometry of the balanced equation, where the coefficient of $\mathrm{NO}_{2}^{-}$ is 3.