Questions: Does the point P=(7,37,1296) lie on the path r=<1+t, 2+t^2, t^4> ? No, it doesn't. Yes, it does. Does the point Q=(-1,7,16) lie on the path r=<1+t, 2+t^2, t^4> ? Yes, it does. No, it doesn't.

Does the point P=(7,37,1296) lie on the path r=<1+t, 2+t^2, t^4> ?
No, it doesn't.
Yes, it does.

Does the point Q=(-1,7,16) lie on the path r=<1+t, 2+t^2, t^4> ?
Yes, it does.
No, it doesn't.
Transcript text: Does the point $P=(7,37,1296)$ lie on the path $\mathbf{r}=\left\langle 1+t, 2+t^{2}, t^{4}\right\rangle$ ? No, it doesn't. Yes, it does. Does the point $Q=(-1,7,16)$ lie on the path $\mathbf{r}=\left\langle 1+t, 2+t^{2}, t^{4}\right\rangle$ ? Yes, it does. No, it doesn't.
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Solution

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Solution Steps

To determine if a point lies on the given path, we need to find a value of \( t \) such that the parametric equations of the path match the coordinates of the point. Specifically, for a point \( (x, y, z) \), we need to solve the system of equations: \( 1 + t = x \), \( 2 + t^2 = y \), and \( t^4 = z \). If a common \( t \) satisfies all three equations, the point lies on the path.

Step 1: Check Point \( P = (7, 37, 1296) \)

To determine if point \( P \) lies on the path defined by \( \mathbf{r} = \langle 1+t, 2+t^2, t^4 \rangle \), we set up the following equations based on the coordinates of \( P \):

  1. \( 1 + t = 7 \)
  2. \( 2 + t^2 = 37 \)
  3. \( t^4 = 1296 \)

Solving these equations, we find:

  1. From \( 1 + t = 7 \), we get \( t = 6 \).
  2. Substituting \( t = 6 \) into \( 2 + t^2 = 37 \) gives \( 2 + 36 = 38 \), which does not hold.
  3. Therefore, point \( P \) does not satisfy all equations.
Step 2: Check Point \( Q = (-1, 7, 16) \)

Next, we check if point \( Q \) lies on the same path. We set up the equations:

  1. \( 1 + t = -1 \)
  2. \( 2 + t^2 = 7 \)
  3. \( t^4 = 16 \)

Solving these equations, we find:

  1. From \( 1 + t = -1 \), we get \( t = -2 \).
  2. Substituting \( t = -2 \) into \( 2 + t^2 = 7 \) gives \( 2 + 4 = 6 \), which does not hold.
  3. Therefore, point \( Q \) does not satisfy all equations.

Final Answer

Point \( P \) does not lie on the path, and point \( Q \) does not lie on the path either. Thus, the answers are:

  • For point \( P \): No, it doesn't.
  • For point \( Q \): No, it doesn't.

The final answers are: \(\boxed{\text{No, it doesn't for } P}\) \(\boxed{\text{No, it doesn't for } Q}\)

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