Questions: Problem 3: (9% of Assignment Value) A pebble is dropped from rest from the top of a building. It takes Δt=3.29 s for it to reach the ground. Use the coordinate axes provide in the image. Part (a) What is the initial velocity, in meters per second, of the pebble? vi= m / s

Solution Steps

• The pebble is dropped from rest, so the initial velocity \( v_i = 0 \) m/s.
• The time taken to reach the ground \( \Delta t = 3.29 \) s.
• The acceleration due to gravity \( g = 9.8 \) m/s².

The kinematic equation for an object in free fall is: \[ y = v_i t + \frac{1}{2} g t^2 \] Since \( v_i = 0 \): \[ y = \frac{1}{2} g t^2 \]

\[ y = \frac{1}{2} \times 9.8 \times (3.29)^2 \] \[ y = \frac{1}{2} \times 9.8 \times 10.8241 \] \[ y = 5.4 \times 10.8241 \] \[ y = 52.03 \text{ meters} \]

Final Answer