Questions: A card is drawn randomly from a standard 52-card deck. Find the probability of the given event. Write your answers as reduced fractions or whole numbers.
(a) The card drawn is 5
P(5)=
(b) The card drawn is the 5 of clubs.
P(5 of clubs )=
Transcript text: A card is drawn randomly from a standard 52-card deck. Find the probability of the given event. Write your answers as reduced fractions or whole numbers.
(a) The card drawn is 5
\[
P(5)=
\]
$\square$
(b) The card drawn is the 5 of clubs.
$P(5$ of clubs $)=$ $\square$
Solution
Solution Steps
To solve these probability questions, we need to determine the number of favorable outcomes and divide it by the total number of possible outcomes. For a standard 52-card deck, the total number of possible outcomes is 52.
(a) To find the probability of drawing a 5, we count the number of 5s in the deck. There are four 5s (one for each suit: hearts, diamonds, clubs, and spades).
(b) To find the probability of drawing the 5 of clubs, we consider that there is only one 5 of clubs in the deck.
Step 1: Total Outcomes
In a standard deck of cards, the total number of cards is given by:
\[
\text{Total outcomes} = 52
\]
Step 2: Probability of Drawing a 5
The number of favorable outcomes for drawing a 5 (which includes the 5 of hearts, 5 of diamonds, 5 of clubs, and 5 of spades) is:
\[
\text{Favorable outcomes for 5} = 4
\]
Thus, the probability \( P(5) \) is calculated as:
\[
P(5) = \frac{\text{Favorable outcomes for 5}}{\text{Total outcomes}} = \frac{4}{52} = \frac{1}{13}
\]
Step 3: Probability of Drawing the 5 of Clubs
The number of favorable outcomes for drawing the 5 of clubs is:
\[
\text{Favorable outcomes for 5 of clubs} = 1
\]
Therefore, the probability \( P(5 \text{ of clubs}) \) is:
\[
P(5 \text{ of clubs}) = \frac{\text{Favorable outcomes for 5 of clubs}}{\text{Total outcomes}} = \frac{1}{52}
\]
Final Answer
The probabilities are:
\[
P(5) = \frac{1}{13}, \quad P(5 \text{ of clubs}) = \frac{1}{52}
\]
Thus, the final answers are:
\[
\boxed{P(5) = \frac{1}{13}, \quad P(5 \text{ of clubs}) = \frac{1}{52}}
\]