To solve the expression \[ \frac{2x + 16}{8x - 5} \div \frac{x + 8}{2x - 8}, \] we rewrite the division as multiplication by the reciprocal: \[ \frac{2x + 16}{8x - 5} \times \frac{2x - 8}{x + 8}. \]
Next, we factor the numerator and denominator of the resulting expression:
Thus, we have: \[ \frac{2(x + 8)}{8x - 5} \times \frac{2(x - 4)}{x + 8}. \]
Now, we can simplify the expression by canceling the common factor \(x + 8\): \[ \frac{2 \cdot 2(x - 4)}{8x - 5} = \frac{4(x - 4)}{8x - 5}. \]
The simplified result of the original expression is: \[ \boxed{\frac{4(x - 4)}{8x - 5}}. \]
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