We start with the integral
∫14x4 dx. \int \frac{1}{4 x^{4}} \, dx. ∫4x41dx.
This can be rewritten as
∫14x−4 dx. \int \frac{1}{4} x^{-4} \, dx. ∫41x−4dx.
Using the power rule for integration, we have
∫x−4 dx=x−3−3+C=−13x3+C. \int x^{-4} \, dx = \frac{x^{-3}}{-3} + C = -\frac{1}{3 x^{3}} + C. ∫x−4dx=−3x−3+C=−3x31+C.
Thus, incorporating the constant factor 14\frac{1}{4}41, we get
∫14x−4 dx=14(−13x3+C)=−112x3+C. \int \frac{1}{4} x^{-4} \, dx = \frac{1}{4} \left(-\frac{1}{3 x^{3}} + C\right) = -\frac{1}{12 x^{3}} + C. ∫41x−4dx=41(−3x31+C)=−12x31+C.
The result of the indefinite integral is
−112x3+C. \boxed{-\frac{1}{12 x^{3}} + C}. −12x31+C.
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