Questions: f(x)=(5x^2+3x-2)/(x^3-8)

f(x)=(5x^2+3x-2)/(x^3-8)
Transcript text: $f(x)=\frac{5 x^{2}+3 x-2}{x^{3}-8}$
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Solution

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To analyze the function \( f(x) = \frac{5x^2 + 3x - 2}{x^3 - 8} \), we can perform several tasks such as finding its domain, identifying any asymptotes, and calculating its derivative. Here, we'll focus on finding the derivative of the function using the quotient rule.

  1. Quotient Rule: The derivative of a quotient \(\frac{u}{v}\) is given by \(\frac{u'v - uv'}{v^2}\), where \(u = 5x^2 + 3x - 2\) and \(v = x^3 - 8\).
  2. Calculate Derivatives: Compute \(u'\) and \(v'\), the derivatives of the numerator and the denominator, respectively.
  3. Apply the Quotient Rule: Substitute \(u\), \(v\), \(u'\), and \(v'\) into the quotient rule formula to find \(f'(x)\).
Paso 1: Derivadas de \(u\) y \(v\)

Dado \(u = 5x^2 + 3x - 2\) y \(v = x^3 - 8\), calculamos las derivadas:

\[ u' = \frac{d}{dx}(5x^2 + 3x - 2) = 10x + 3 \]

\[ v' = \frac{d}{dx}(x^3 - 8) = 3x^2 \]

Paso 2: Aplicación de la Regla del Cociente

La regla del cociente establece que la derivada de \(\frac{u}{v}\) es:

\[ f'(x) = \frac{u'v - uv'}{v^2} \]

Sustituyendo los valores calculados:

\[ f'(x) = \frac{(10x + 3)(x^3 - 8) - (5x^2 + 3x - 2)(3x^2)}{(x^3 - 8)^2} \]

Respuesta Final

La derivada de la función \(f(x) = \frac{5x^2 + 3x - 2}{x^3 - 8}\) es:

\[ \boxed{f'(x) = \frac{(10x + 3)(x^3 - 8) - (5x^2 + 3x - 2)(3x^2)}{(x^3 - 8)^2}} \]

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