To find the exact value of each logarithm, we need to determine the exponent that the base must be raised to in order to get the given number.
a. For $\log _{7} 49$, we need to find the exponent \( x \) such that \( 7^x = 49 \).
b. For $\log _{4} 4$, we need to find the exponent \( x \) such that \( 4^x = 4 \).
c. For $\log _{1 / 2} 32$, we need to find the exponent \( x \) such that \( (1/2)^x = 32 \).
To find \(\log _{7} 49\), we need to determine the exponent \( x \) such that \( 7^x = 49 \).
Since \( 49 = 7^2 \), we have:
\[ 7^x = 7^2 \]
Thus, \( x = 2 \).
To find \(\log _{4} 4\), we need to determine the exponent \( x \) such that \( 4^x = 4 \).
Since \( 4 = 4^1 \), we have:
\[ 4^x = 4^1 \]
Thus, \( x = 1 \).
To find \(\log _{1 / 2} 32\), we need to determine the exponent \( x \) such that \( \left(\frac{1}{2}\right)^x = 32 \).
Since \( 32 = 2^5 \), we can rewrite the equation as:
\[ \left(\frac{1}{2}\right)^x = 2^5 \]
This implies:
\[ 2^{-x} = 2^5 \]
Thus, \( -x = 5 \) and \( x = -5 \).