Questions: Here is probability data on a random sample of students who have enrolled in a Business-related Math course...
PASS FAIL Withdrew TOTAL
--------------------------------------
Calculus .36 .05 .03 .44
Statistics .45 .04 .07 .56
TOTAL .81 .09 .10 1
Compute the probability of passing the course given that the course taken was statistics.
P(pass stat) = P(pass ∩ stat) / P(stat)
Transcript text: Here is probability data on a random sample of students who have enrolled in a Business-related Math course...
\begin{tabular}{lllll}
& PASS & FAIL & \multicolumn{2}{l}{ WithdrewTOTAL } \\
Calculus .36 & .05 & .03 & .44 \\
Statistics .45 & .04 & .07 & .56 \\
TOTAL .81 & .09 & .10 & 1
\end{tabular}
Compute the probability of passing the course given that the course taken was statistics.
$P($ pass $\mid$ stat $)=\frac{P(\text { pass } \cap \text { stat })}{P(\text { stat })}$
Solution
Solution Steps
To find the probability of passing the course given that the course taken was statistics, we use the conditional probability formula: \( P(\text{pass} \mid \text{stat}) = \frac{P(\text{pass} \cap \text{stat})}{P(\text{stat})} \). From the data, \( P(\text{pass} \cap \text{stat}) \) is the probability of passing statistics, and \( P(\text{stat}) \) is the total probability of taking statistics.
Step 1: Identify Given Probabilities
We are given the following probabilities from the data:
\( P(\text{pass} \cap \text{stat}) = 0.45 \)
\( P(\text{stat}) = 0.56 \)
Step 2: Apply the Conditional Probability Formula
To find the conditional probability \( P(\text{pass} \mid \text{stat}) \), we use the formula:
\[
P(\text{pass} \mid \text{stat}) = \frac{P(\text{pass} \cap \text{stat})}{P(\text{stat})}
\]
Step 3: Substitute the Values
Substituting the known values into the formula:
\[
P(\text{pass} \mid \text{stat}) = \frac{0.45}{0.56}
\]