Questions: Here is probability data on a random sample of students who have enrolled in a Business-related Math course... PASS FAIL Withdrew TOTAL -------------------------------------- Calculus .36 .05 .03 .44 Statistics .45 .04 .07 .56 TOTAL .81 .09 .10 1 Compute the probability of passing the course given that the course taken was statistics. P(pass stat) = P(pass ∩ stat) / P(stat)

Here is probability data on a random sample of students who have enrolled in a Business-related Math course...

          PASS  FAIL  Withdrew  TOTAL 
--------------------------------------
 Calculus .36   .05   .03       .44   
 Statistics .45 .04   .07       .56   
 TOTAL    .81   .09   .10       1     

Compute the probability of passing the course given that the course taken was statistics.

P(pass  stat) = P(pass ∩ stat) / P(stat)
Transcript text: Here is probability data on a random sample of students who have enrolled in a Business-related Math course... \begin{tabular}{lllll} & PASS & FAIL & \multicolumn{2}{l}{ WithdrewTOTAL } \\ Calculus .36 & .05 & .03 & .44 \\ Statistics .45 & .04 & .07 & .56 \\ TOTAL .81 & .09 & .10 & 1 \end{tabular} Compute the probability of passing the course given that the course taken was statistics. $P($ pass $\mid$ stat $)=\frac{P(\text { pass } \cap \text { stat })}{P(\text { stat })}$
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Solution

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Solution Steps

To find the probability of passing the course given that the course taken was statistics, we use the conditional probability formula: \( P(\text{pass} \mid \text{stat}) = \frac{P(\text{pass} \cap \text{stat})}{P(\text{stat})} \). From the data, \( P(\text{pass} \cap \text{stat}) \) is the probability of passing statistics, and \( P(\text{stat}) \) is the total probability of taking statistics.

Step 1: Identify Given Probabilities

We are given the following probabilities from the data:

  • \( P(\text{pass} \cap \text{stat}) = 0.45 \)
  • \( P(\text{stat}) = 0.56 \)
Step 2: Apply the Conditional Probability Formula

To find the conditional probability \( P(\text{pass} \mid \text{stat}) \), we use the formula: \[ P(\text{pass} \mid \text{stat}) = \frac{P(\text{pass} \cap \text{stat})}{P(\text{stat})} \]

Step 3: Substitute the Values

Substituting the known values into the formula: \[ P(\text{pass} \mid \text{stat}) = \frac{0.45}{0.56} \]

Step 4: Calculate the Result

Calculating the above expression gives: \[ P(\text{pass} \mid \text{stat}) \approx 0.8036 \]

Final Answer

Thus, the probability of passing the course given that the course taken was statistics is: \[ \boxed{0.8036} \]

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